Series Program
In c language you can print any number series. Here i will show you how to print number series in c language with explanation. In case of print number series you need to focus on common difference between two numbers..
C program to Calculate [(1^1)/1] + [(2^2)/2] + [(3^3)/3] + [(4^4)/4] + [(5^5)/5] + ... + [(n^n)/n] series
#include<stdio.h>
#include<math.h>
long power(int a, int b)
{
long i, p=1;
for(i=1;i<=b;i++)
{
p=p*a;
}
return p;
}
int main()
{
long i,n;
double sum=0;
n=5;
for(i=1;i<=n;i++)
{
sum=sum+(power(i,i)/i);
}
printf("Sum: %lf",sum);
return 0;
}
Output:
sum: 701.000000
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
long power(int a, int b)
{
long i, p=1;
for(i=1;i<=b;i++)
{
p=p*a;
}
return p;
}
int main()
{
long i,n;
double sum=0;
printf("\n Enter n value [(1^1)/1] + [(2^2)/2] + [(3^3)/3] + [(4^4)/4] + [(5^5)/5] + ... + [(n^n)/n]:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
sum=sum+(power(i,i)/i);
}
printf("Sum: %lf",sum);
return 0;
}
