C program to Calculate (1!/1) + (2!/2) + (3!/3) + (4!/4) + (5!/5) + ... + (n!/n) series

Series Program

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• C Programming Exercises
• Basic C programming exercises
• Bitwise operator exercises
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• Number pattern exercises
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• String exercises
• Pointer exercises
• Files handling exercises

Program to Print Number Series in C

In c language you can print any number series. Here i will show you how to print number series in c language with explanation. In case of print number series you need to focus on common difference between two numbers..

C program to Calculate (1!/1) + (2!/2) + (3!/3) + (4!/4) + (5!/5) + ... + (n!/n) series

#include<stdio.h>
long fact(int n)
{
    long i, f=1;
    for(i=1;i<=n;i++)
    {
        f=f*i;
    }
    return f;
}

int main()
{
    long i,n;
    double sum=0;
    n=5;
    for(i=1;i<=n;i++)
    {
        sum=sum+(fact(i)/i);
    }
    printf("Sum: %lf",sum);
    return 0;
}

Output:

sum: 34.000000

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
long fact(int n)
{
    long i, f=1;
    for(i=1;i<=n;i++)
    {
        f=f*i;
    }
    return f;
}

int main()
{
    long i,n;
    double sum=0;
    printf("\n Enter n value (1!/1) + (2!/2) + (3!/3) + (4!/4) + (5!/5) + ... + (n!/n):");
    scanf("%d",&n);
    for(i=1;i<=n;i++)
    {
        sum=sum+(fact(i)/i);
    }
    printf("Sum: %lf",sum);
    return 0;
}

Output:

Enter n value (1!/1) + (2!/2) + (3!/3) + (4!/4) + (5!/5) + ... + (n!/n):10
Sum: 409114.000000
Process returned 0 (0x0)   execution time : 2.145 s

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