Series Program
In c language you can print any number series. Here i will show you how to print number series in c language with explanation. In case of print number series you need to focus on common difference between two numbers..
C program to Calculate [(1^1)/1!] + [(2^2)/2!] + [(3^3)/3!] + [(4^4)/4!] + [(5^5)/5!] + ... + [(n^n)/n!] series
#include<stdio.h> #include<math.h> double power(int a, int b) { long i, p=1; for(i=1;i<=b;i++) { p=p*a; } return p; } double fact(int n) { long i, f=1; for(i=1;i<=n;i++) { f=f*i; } return f; } int main() { long i,n; double sum=0; n=5; for(i=1;i<=n;i++) { sum=sum+power(i,i)/fact(i); } printf("Sum: %lf",sum); return 0; }
Output:
Sum: 44.208333
#include <stdio.h> #include <stdlib.h> #include <math.h> double power(int a, int b) { long i, p=1; for(i=1;i<=b;i++) { p=p*a; } return p; } double fact(int n) { long i, f=1; for(i=1;i<=n;i++) { f=f*i; } return f; } int main() { long i,n; double sum=0; printf("\n Enter n value [(1^1)/1!] + [(2^2)/2!] + [(3^3)/3!] + [(4^4)/4!] + [(5^5)/5!] + ... + [(n^n)/n!]:"); scanf("%d",&n); for(i=1;i<=n;i++) { sum=sum+power(i,i)/fact(i); } printf("Sum: %lf",sum); return 0; }