Series Program
In c language you can print any number series. Here i will show you how to print number series in c language with explanation. In case of print number series you need to focus on common difference between two numbers..
C program to Calculate [(1^1)/1!] + [(2^2)/2!] + [(3^3)/3!] + [(4^4)/4!] + [(5^5)/5!] + ... + [(n^n)/n!] series
#include<stdio.h>
#include<math.h>
double power(int a, int b)
{
long i, p=1;
for(i=1;i<=b;i++)
{
p=p*a;
}
return p;
}
double fact(int n)
{
long i, f=1;
for(i=1;i<=n;i++)
{
f=f*i;
}
return f;
}
int main()
{
long i,n;
double sum=0;
n=5;
for(i=1;i<=n;i++)
{
sum=sum+power(i,i)/fact(i);
}
printf("Sum: %lf",sum);
return 0;
}
Output:
Sum: 44.208333
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
double power(int a, int b)
{
long i, p=1;
for(i=1;i<=b;i++)
{
p=p*a;
}
return p;
}
double fact(int n)
{
long i, f=1;
for(i=1;i<=n;i++)
{
f=f*i;
}
return f;
}
int main()
{
long i,n;
double sum=0;
printf("\n Enter n value [(1^1)/1!] + [(2^2)/2!] + [(3^3)/3!] + [(4^4)/4!] + [(5^5)/5!] + ... + [(n^n)/n!]:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
sum=sum+power(i,i)/fact(i);
}
printf("Sum: %lf",sum);
return 0;
}
